![]() ![]() Light-to-heat generation and light-to-electricity conversion have recently seen research progress. The traditional laser power conversion configuration is usually applied to photovoltaic (PV) cells. 9,10 However, laser-induced damage of the aluminum alloy frame for the entire system has not been comprehensively studied, especially via theoretical research. For this process, damage to optical elements such as fused silica and potassium dihydrogen phosphate (KDP) is an important topic of research. 6 The French Megajoule Laser Project (LMJ) supported by the French Atomic Energy Commission (CEA) 7 and the American National Ignition Facility Project (NIF) are collaborating with Lawrence Berkeley National Laboratory 8 to realize this goal. ![]() 3–5 A nuclear laser facility can reach 1.8 MJ and 500 TW of 355 nm light in 10 −9 s, which is equivalent to 1000 times the energy consumption of the United States. 2 Because of its potential advantages for quickly generating a large, inexhaustible amount of clean energy. Hence, tritium in fusion reactors needs to be recycled, using doubled neutrons for reaction with lithium followed by recovery of tritium, where tritium functions like a catalyst (reaction shown in eqn (2)). However, the half-life of tritium (T) is short and it does not occur naturally furthermore, it is extremely difficult to obtain via reaction. For example copper has a high absorption in the red and low one in blue resulting in a reddish color.Laser-driven inertial confinement fusion (ICF) can generate large amounts of renewable energy via the chemical reaction of two forms of hydrogen-deuterium (D) and tritium (T) 1-and the reaction is expressed in eqn (1). Higher absorption of a color now means that it looks more like that color because higher imaginary part means higher reflectivity. Refractive index has a high imaginary part (e.g. Rust has an absorption peak around 400 nm (blue) and therefore looks reddish. ![]() Dispersion of the imaginary part determines the color. the light transmitted into the substance is absorbed. few percent are reflected but in contrast to 1. Refractive index has a low imaginary part (e.g. Dispersion is only visible in certain geometries for example prism or rainbow. Refractive index is purely real in the wavelength region of interest => no absorption (e.g. There are now certain possibilities for the refractive index: For the object to have color the refractive index has to change with wavelength, which we call dispersion. They only depend on the the geometry of the problem, the refractive index of the object and the wavelength of the light. Transmission and reflection are well described by the fresnel equations. When you ask what color has an object the physics question you ask is what light is reflected or transmitted by the object to your eye. The real part determines the wavelength of light in matter and the imaginary part describes absorption of light in matter. The reason why it is not obvious is that one has to takes the imaginary part of the refractive index into account. The color of an object is completely determined by the refractive index and the geometry of the object. ![]()
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